Our website is made possible by displaying online advertisements to our visitors.

Please consider supporting us by disabling your ad blocker.
Sign in to follow this  
Followers 0
Cinnamon

Facebook Wants to Help Sell Every Ad on the Web

2 posts in this topic

By 

JACK MARSHALL

May 27, 2016 12:00 a.m. ET

Facebook has set out to power all advertising across the Internet.

To that end, the social network and online advertising company said Thursday it will now help marketers show ads to all users who visit websites and applications in its Audience Network ad network. Previously Facebook only showed ads to members of its social network when they visited those third-party properties.

The change is a subtle one, but it could mean Facebook will soon help to sell and place a much larger portion of the video and display ads that appear across the Internet. The change will also intensify competition with Alphabet Inc. subsidiary Google, which dominates the global digital-advertising market, and a wide range of other online ad specialists.

“Publishers and app developers have some users who aren’t Facebook users. We think we can do a better job powering those ads,” said Andrew Bosworth, vice president of Facebook’s ads and business platform.

Facebook disclosed in March that about 1.65 billion people now use the site each month. According to the International Telecommunication Union, a total of 3.17 billion people used the Internet globally in 2015.

<snip>

http://www.wsj.com/articles/facebook-wants-to-help-sell-every-ad-on-the-web-1464321603

I need an Octopus meme for this one.  

1 person likes this

Share this post


Link to post
Share on other sites

 

Edited by JibbyJedi
1 person likes this

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up to our community. It's easy!


Register a new account

Sign in

Already have an account? Sign in here.


Sign In Now
Sign in to follow this  
Followers 0